Answer:
As 0≤cos
−1
θ≤π
For cos
x+cos
y+cos
z=3π this to true
⇒cos
x=cos
y=cos
z=π
⇒x=y=z=−1
∴∑xy=xy+yz+zx=(−1)
2
+(−1)
=3
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Verified answer
Answer:
As 0≤cos
−1
θ≤π
For cos
−1
x+cos
−1
y+cos
−1
z=3π this to true
⇒cos
−1
x=cos
−1
y=cos
−1
z=π
⇒x=y=z=−1
∴∑xy=xy+yz+zx=(−1)
2
+(−1)
2
+(−1)
2
=3