If an object of 10 cm height is placed at a distance of 36 cm from a concave mirror of focal length 12 cm , find the position , nature and height of image.
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=1/(-12) - 1/(-36)
= -2/36 = -1/18
therefore , v = -18
now magnification M = image height / object height = -v/u
i.e, image height = 10 x -(-18)/-36
= 10 x (-1/2)
= -5
Therefore, image would be real and inverted
since , 1/v = 1/f - 1/u
=1/(-12) - 1/(-36)
= -2/36 = -1/18
therefore , v = -18
now magnification M = image height / object height = -v/u
i.e, image height = 10 x -(-18)/-36
= 10 x (-1/2)
= -5
Therefore, image would be real and inverted
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