Right question:
If a and B are the zeros of the quadratic polynomial f(x) = 5x² - 7x + 1, find the value of 1/a + 1/8
Given:
a and B are the zeros of the polynomial f(x) = 5x² - 7x + 1
To find:
a/B + Bla
Solution:
In the equation given above,
a = 5,
b = -7, and
C = 1
a + B = -b/a = -(-7)/5 = 7/5
a B = c/a = 1/5Now,
1/a + 1/8 = a + ßlaß
= 7/5/1/5
= 7/5 × 5/1
= 7
Hope it helps you bro.
Answer:
7x²+2x-5=0
a+b=-2/7
ab=-5/7
[tex]\sf{\dfrac{a}{b} + \dfrac{b}{a} = \dfrac{a {}^{2} + b {}^{2} }{ab}}[/tex]
a²+b²=(a+b)²-2ab=74/49
[tex]\sf{\dfrac{a}{b} + \dfrac{b}{a} = - \dfrac{74}{35}}[/tex]
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Answers & Comments
Right question:
If a and B are the zeros of the quadratic polynomial f(x) = 5x² - 7x + 1, find the value of 1/a + 1/8
Given:
a and B are the zeros of the polynomial f(x) = 5x² - 7x + 1
To find:
a/B + Bla
Solution:
In the equation given above,
a = 5,
b = -7, and
C = 1
a + B = -b/a = -(-7)/5 = 7/5
a B = c/a = 1/5Now,
1/a + 1/8 = a + ßlaß
= 7/5/1/5
= 7/5 × 5/1
= 7
Hope it helps you bro.
Answer:
7x²+2x-5=0
a+b=-2/7
ab=-5/7
[tex]\sf{\dfrac{a}{b} + \dfrac{b}{a} = \dfrac{a {}^{2} + b {}^{2} }{ab}}[/tex]
a²+b²=(a+b)²-2ab=74/49
ab=-5/7
[tex]\sf{\dfrac{a}{b} + \dfrac{b}{a} = - \dfrac{74}{35}}[/tex]