Answer:
GIVEN:
A=(x²+y²+3); B=(3x²y-2y²+5)
SOLUTION: we have to find the co-efficient of y² in A-B, so first find the A-B value
=3x²y-x²+y²-2y²+3+5
=x²(3y-1)-y²+8
"the co-efficient of y² is -1"
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Verified answer
Answer:
GIVEN:
A=(x²+y²+3); B=(3x²y-2y²+5)
SOLUTION: we have to find the co-efficient of y² in A-B, so first find the A-B value
=3x²y-x²+y²-2y²+3+5
=x²(3y-1)-y²+8
"the co-efficient of y² is -1"