The height from which the stone is dropped = hAcceleration due to gravity experienced = gInitial velocity , u = 0To find :The time taken by the stone to reach on the ground .Solution :Let the time taken by the stone to reach the ground be t .By using 2nd equation motion , distance = initial velocity * time taken + (1/2) * acceleration * time * time=> -h = u * t - (1/2) * g * t * t( minus sign for height and g as per convention )=> -h = - (1/2) * g * t * t=> t = is the time taken by the stone to reach on the groundWhere u is initial velocity, ‘s’ is distance travelled (Height of the tower in this case), ‘t’ is time travelled and ‘a’ is the constant acceleration.So , here as the object is dropped , the initial velocity ,u is 0Acceleration is the acceleration due to gravity ‘g’ which is constant and has value of 9.8m/ s2 Time travelled is given as t=10 seconds
Substituting the values in the equation
s=ut+( 1/2) a t2 we gets=0 * 10 + ( 1/2) * 9.8 * 10 *10s=490 meters
So, the height of the tower is 490 meters
For this question we can use Newton's 2 equations=ut +1/2at^2.
Here h is s and g is 10(we generally consider gravity as 10)
Answers & Comments
Answer:
367.5
Explanation:
122.5 × 3 is 367.5
The height from which the stone is dropped = hAcceleration due to gravity experienced = gInitial velocity , u = 0To find :The time taken by the stone to reach on the ground .Solution :Let the time taken by the stone to reach the ground be t .By using 2nd equation motion , distance = initial velocity * time taken + (1/2) * acceleration * time * time=> -h = u * t - (1/2) * g * t * t( minus sign for height and g as per convention )=> -h = - (1/2) * g * t * t=> t = is the time taken by the stone to reach on the groundWhere u is initial velocity, ‘s’ is distance travelled (Height of the tower in this case), ‘t’ is time travelled and ‘a’ is the constant acceleration.So , here as the object is dropped , the initial velocity ,u is 0Acceleration is the acceleration due to gravity ‘g’ which is constant and has value of 9.8m/ s2 Time travelled is given as t=10 seconds
Substituting the values in the equation
s=ut+( 1/2) a t2 we gets=0 * 10 + ( 1/2) * 9.8 * 10 *10s=490 meters
So, the height of the tower is 490 meters
For this question we can use Newton's 2 equations=ut +1/2at^2.
Here h is s and g is 10(we generally consider gravity as 10)
u=initial velocity which is 0
Therefore
H = 5t^2t=√h/√5.the value of t is as Above
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