Answer:
KE = ½ mv²
KE = ½ 1000kg (17 m/s²)
KE = 144,500
Explanation:
KE = Kinetic Energy
m = mass of the object
v = speed / velocity of the object
If the same 1.0 kg book is lifted 0.5 above the table, but the table top is 1.0m above the floor, what would be the potential energy of the book if the reference level were the floor?
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Answer:
KE = ½ mv²
KE = ½ 1000kg (17 m/s²)
KE = 144,500
Explanation:
KE = Kinetic Energy
m = mass of the object
v = speed / velocity of the object
If the same 1.0 kg book is lifted 0.5 above the table, but the table top is 1.0m above the floor, what would be the potential energy of the book if the reference level were the floor?
KE = ½ mv²
KE = ½ 1000kg (17 m/s²)
KE = 144,500