If 8 men and 8 boys can do a piece of work in 10 days and 26 men and 48 boys can complete the work in 2 days then in how many days the work will be completed by 15 men and 20 boys?
If 6 men and 8 boys can do a piece of work in 10 days and 26 men and 48 boys can do the same work in 2 days then the time taken by 15 men and 20 boys to do the same type of work
Answers & Comments
Answer:
If 6 men and 8 boys can do a piece of work in 10 days and 26 men and 48 boys can do the same work in 2 days then the time taken by 15 men and 20 boys to do the same type of work
Explanation:
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Verified answer
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
Then, 6x + 8y = 1/10 and 26x + 48y = 1/2,.
Solving these two equations, we get : x = 1/100 and y = 1/200 .
(15 men + 20 boy)'s 1 day's work = (15/100 + 20/200) = 1/4
So, 15 men and 20 boys can do the work in 4 days.
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