Answer:
1 mole (44 g) of CO2 contain 32 g of O2
Thus, 32 g of oxygen is present in 1 mole of CO2
So, 8g of oxygen is present in (1/32) x 8 = 0.25 mole of CO2 = 0.25 x 6.022 x 10^23 = 1.5055 x 10^23 molecules of CO2
Explanation:
it has 1 mole thus 32g of oxygen is present in (1/32)
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Answer:
1 mole (44 g) of CO2 contain 32 g of O2
Thus, 32 g of oxygen is present in 1 mole of CO2
So, 8g of oxygen is present in (1/32) x 8 = 0.25 mole of CO2 = 0.25 x 6.022 x 10^23 = 1.5055 x 10^23 molecules of CO2
Explanation:
it has 1 mole thus 32g of oxygen is present in (1/32)