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taqia
@taqia
July 2022
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if -5 is root of the quadratic equation 2xsquare+px-15=0 and the quadratic equation p(xsquare+x)+k=0 has equal roots find the value of k
Answers & Comments
rijitasingh
2×(-5)×(-5)+p(-5)-15=0
50+75p=0
75p= -50
p= -50/75
now put value of in 2nd eq
and used formula
D=b×b-4bc
0 votes
Thanks 2
rijitasingh
mark me as brainly
taqia
thankss
ANWAR21
-5 is the root of the equ
so 2×-5 square +p×-5-15=0
p=15-50/-5=7
now
7×(x square +x)+k=0
7x square +7x+k=0
for equal root D=0
D=b square -4ac=0
49-28k=0
k=-49/-28
k=7/4
4 votes
Thanks 2
taqia
thankss
rijitasingh
welcome
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Answers & Comments
50+75p=0
75p= -50
p= -50/75
now put value of in 2nd eq
and used formula
D=b×b-4bc
so 2×-5 square +p×-5-15=0
p=15-50/-5=7
now
7×(x square +x)+k=0
7x square +7x+k=0
for equal root D=0
D=b square -4ac=0
49-28k=0
k=-49/-28
k=7/4