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Ankit1234
@Ankit1234
September 2021
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If -3 is the zero of (k-1)x² + kx + 1.
Find the value of k
Answers & Comments
maria9
Verified answer
Zero = -3
by putting -3 in place of x, we get
(k-1)-3² + k (-3) + 1 = 0
(k-1)9 -3k + 1 = 0
9k-9 - 3k+1 = 0
6k -8 = 0
k = 8/6
= 4/3
4 votes
Thanks 7
deepikakvvk06
Verified answer
Hi !
p(x) =
(k-1)x² + kx + 1.
p(-3) = 0
x = -3
Putting this value of x in p(x)
(k-1)x² + kx + 1 = 0
(k-1)*(-3)
² + k*-3 + 1 = 0
9(k-1) - 3k + 1 = 0
9k - 9 - 3k + 1 = 0
6k -8 = 0
6k = 8
k = 8/6
k = 4/3
Value of k is 4/3
1 votes
Thanks 9
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Answers & Comments
Verified answer
Zero = -3by putting -3 in place of x, we get
(k-1)-3² + k (-3) + 1 = 0
(k-1)9 -3k + 1 = 0
9k-9 - 3k+1 = 0
6k -8 = 0
k = 8/6
= 4/3
Verified answer
Hi !p(x) = (k-1)x² + kx + 1.
p(-3) = 0
x = -3
Putting this value of x in p(x)
(k-1)x² + kx + 1 = 0
(k-1)*(-3)² + k*-3 + 1 = 0
9(k-1) - 3k + 1 = 0
9k - 9 - 3k + 1 = 0
6k -8 = 0
6k = 8
k = 8/6
k = 4/3
Value of k is 4/3