Answer:
[tex] \sqrt{ 22 + } \sqrt{8} = \sqrt{15a} + b \sqrt{11} \\ \sqrt{2} \sqrt{11} + \sqrt{4} . \sqrt{2} \\ a + b - 10 \\ b = 10 - a[/tex]
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Answer:
[tex] \sqrt{ 22 + } \sqrt{8} = \sqrt{15a} + b \sqrt{11} \\ \sqrt{2} \sqrt{11} + \sqrt{4} . \sqrt{2} \\ a + b - 10 \\ b = 10 - a[/tex]
ur answer
hope its helps uuu ......
Step-by-step explanation:
...
ur answer
hope it will helps uuu ......