Answer:

Problem:

if 200 J of energy is added to a system when no external work has been done, by how much will the thermal energy of the system be raised​

Given Data:

Q (energy added) = 200 J

W (work done) = 0 J

ΔU (change in the internal energy ) = ? unknown

Solution:  

We can solve this problem using the formula ΔU = Q - W

ΔU = Q - W

    = 200 J  - 0 J

   = 200 J

Answer:

the change in the internal energy of the gas is 200 J

hope it helps :)