To find the molarity of the NH4Cl solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution in liters
First, we need to calculate the number of moles of NH4Cl present in the solution. We can do this using the formula:
moles of solute = mass of solute / molar mass of solute
The molar mass of NH4Cl is 53.49 g/mol, so:
moles of NH4Cl = 15.4 g / 53.49 g/mol
moles of NH4Cl = 0.288 moles
Next, we need to calculate the volume of the solution in liters, which is given as 900 mL. We need to convert this to liters by dividing by 1000:
volume of solution = 900 mL / 1000
volume of solution = 0.9 L
Now, we can plug in the values we have found into the formula for molarity:
Molarity (M) = 0.288 moles / 0.9 L
Molarity (M) = 0.32 M
Therefore, the molarity of the NH4Cl solution is 0.32 M.
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To find the molarity of the NH4Cl solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution in liters
First, we need to calculate the number of moles of NH4Cl present in the solution. We can do this using the formula:
moles of solute = mass of solute / molar mass of solute
The molar mass of NH4Cl is 53.49 g/mol, so:
moles of NH4Cl = 15.4 g / 53.49 g/mol
moles of NH4Cl = 0.288 moles
Next, we need to calculate the volume of the solution in liters, which is given as 900 mL. We need to convert this to liters by dividing by 1000:
volume of solution = 900 mL / 1000
volume of solution = 0.9 L
Now, we can plug in the values we have found into the formula for molarity:
Molarity (M) = moles of solute / volume of solution in liters
Molarity (M) = 0.288 moles / 0.9 L
Molarity (M) = 0.32 M
Therefore, the molarity of the NH4Cl solution is 0.32 M.