Certainly! To show that the angles opposite to equal sides of a triangle are equal, let's consider a triangle ABC where sides AB and AC are equal. The corresponding angles opposite to these sides are ∠ABC and ∠ACB.
Now, to prove that ∠ABC = ∠ACB, we can use the fact that the sum of angles in a triangle is always 180 degrees. The angles ∠ABC, ∠ACB, and ∠BAC form the three interior angles of triangle ABC.
Since sides AB and AC are equal, according to the Isosceles Triangle Theorem, the angles opposite these sides are also equal. Therefore, ∠ABC = ∠ACB.
In symbols:
\[ \angle ABC = \angle ACB \]
This proves that the angles opposite to equal sides of a triangle are equal. (¬◡¬)✧
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Answer:
Certainly! To show that the angles opposite to equal sides of a triangle are equal, let's consider a triangle ABC where sides AB and AC are equal. The corresponding angles opposite to these sides are ∠ABC and ∠ACB.
Now, to prove that ∠ABC = ∠ACB, we can use the fact that the sum of angles in a triangle is always 180 degrees. The angles ∠ABC, ∠ACB, and ∠BAC form the three interior angles of triangle ABC.
Since sides AB and AC are equal, according to the Isosceles Triangle Theorem, the angles opposite these sides are also equal. Therefore, ∠ABC = ∠ACB.
In symbols:
\[ \angle ABC = \angle ACB \]
This proves that the angles opposite to equal sides of a triangle are equal. (¬◡¬)✧