Step-by-step explanation:
if x=2/3 and x= -3.So,
a(2/3)²+7(2/3)+b=0
a(4/9)+14/3+b=0
4a/9+14/3+b=0
by taking LCM
4a+42+9b/9=0. Now we will transpose 9 to RHS so we get,
4a+42+9b=0
b=-4a-42/9 ...............1
Now x=-3 So,
a(-3)²+7(-3)+b=0
a(9)-21+b=0
9a-21+b=0
b=-9a+21 .................2
-4a-42/9=-9a+21
-4a-42= 9(-9a+21)
-4a-42=189-81a
-4a+81a=189+42
77a = 231
a=231/77
a= 3
Now we will put this value in the equation 2
9(3)-21+b =0
27-21+b=0
6+b=0
b=-6
Ans: a=3 and b=-6
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Verified answer
Step-by-step explanation:
if x=2/3 and x= -3.So,
a(2/3)²+7(2/3)+b=0
a(4/9)+14/3+b=0
4a/9+14/3+b=0
by taking LCM
4a+42+9b/9=0. Now we will transpose 9 to RHS so we get,
4a+42+9b=0
b=-4a-42/9 ...............1
Now x=-3 So,
a(-3)²+7(-3)+b=0
a(9)-21+b=0
9a-21+b=0
b=-9a+21 .................2
-4a-42/9=-9a+21
-4a-42= 9(-9a+21)
-4a-42=189-81a
-4a+81a=189+42
77a = 231
a=231/77
a= 3
Now we will put this value in the equation 2
9(3)-21+b =0
27-21+b=0
6+b=0
b=-6
Ans: a=3 and b=-6