1.
REPRESENTATION:
L = length
W = width
EQUATION:
L×W = 36
2L + 2W = 26
SOLUTION:
If
W = 9, L = 36/9 = 4
W = 4, L= 36/4 = 9 ✔
(NOTE: the longer line is referred to as length and the shorter one as width)
ANSWER:
WIDTH = 4 ft
LENGTH = 9 ft
~~
No. 2
W+6 = length
(W+6)(W) = 160
W² + 6W - 160 = 0
(W+16)(W-10) = 0
W = -16
W = 10 ✔
(NOTE: Dimensions can't be negative)
L = 10+6 = 16
WIDTH = 10 ft
ftLENGTH = 16 ft
No. 3
x = Time of 1st Machine
x+3 = Time of 2nd Machine
lcd = 2(x)(x + 3)
(NOTE: Use the positive value)
x = 3
x+3 = 6
FOR 1ST MACHINE = 3 hrs
FOE 2ND MACHINE = 6 hrs
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Answers & Comments
1.
REPRESENTATION:
L = length
W = width
EQUATION:
L×W = 36
2L + 2W = 26
SOLUTION:
If
W = 9, L = 36/9 = 4
W = 4, L= 36/4 = 9 ✔
(NOTE: the longer line is referred to as length and the shorter one as width)
ANSWER:
WIDTH = 4 ft
LENGTH = 9 ft
~~
No. 2
REPRESENTATION:
W = width
W+6 = length
EQUATION:
(W+6)(W) = 160
SOLUTION:
W² + 6W - 160 = 0
(W+16)(W-10) = 0
W = -16
W = 10 ✔
(NOTE: Dimensions can't be negative)
L = 10+6 = 16
ANSWER:
WIDTH = 10 ft
ftLENGTH = 16 ft
~~
No. 3
REPRESENTATION:
x = Time of 1st Machine
x+3 = Time of 2nd Machine
EQUATION:
SOLUTION:
lcd = 2(x)(x + 3)
(NOTE: Use the positive value)
If
x = 3
x+3 = 6
ANSWER:
FOR 1ST MACHINE = 3 hrs
FOE 2ND MACHINE = 6 hrs