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akanksha36
@akanksha36
August 2021
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I need the solution for 18th question
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kvnmurty
Verified answer
Option (4) 2 π/3
SHM are : x1 = A Sin ωt
x2 = A Sin (ω t + Ф), with a phase difference.
Let us say, at time t = t1,
x1 = A Sin ω t1 = A / 2
=> ω t1 = π/6 ---(1)
x2 = A sin (ω t1 + Ф) = A / 2
=> ω t1 + Ф = 5π / 6 --- (2)
Subtracting (1) from (2):
Ф = 2π/3
2 votes
Thanks 5
kvnmurty
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Answers & Comments
Verified answer
Option (4) 2 π/3SHM are : x1 = A Sin ωt
x2 = A Sin (ω t + Ф), with a phase difference.
Let us say, at time t = t1,
x1 = A Sin ω t1 = A / 2
=> ω t1 = π/6 ---(1)
x2 = A sin (ω t1 + Ф) = A / 2
=> ω t1 + Ф = 5π / 6 --- (2)
Subtracting (1) from (2): Ф = 2π/3