Step-by-step explanation:
y =−3(x+0)2+5
The range of a parabola that opens down starts at its vertex (0,5)(0,5) and extends to negative infinity.
vertex:(0,5)
Domain: (−∞,∞),{x|x∈R}(-∞,∞),{x|x∈ℝ}
Range: (−∞,5],{y|y≤5}
axis of symmetry:
x=0
x intercept:
y-intercept(s): (0,5)
2) Domain: (−∞,∞),{x|x∈R}(-∞,∞),{x|x∈ℝ}
Range: [−8,∞),{y|y≥−8}
*The range of a parabola that opens up starts at its vertex (1,−8)(1,-8) and extends to infinity.
(x = 1)
x intercept: (3,0) (-1,0)
y intercept: (0,-6)
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Answers & Comments
Step-by-step explanation:
y =−3(x+0)2+5
The range of a parabola that opens down starts at its vertex (0,5)(0,5) and extends to negative infinity.
vertex:(0,5)
Domain: (−∞,∞),{x|x∈R}(-∞,∞),{x|x∈ℝ}
Range: (−∞,5],{y|y≤5}
axis of symmetry:
x=0
x intercept:
y-intercept(s): (0,5)
2) Domain: (−∞,∞),{x|x∈R}(-∞,∞),{x|x∈ℝ}
Range: [−8,∞),{y|y≥−8}
*The range of a parabola that opens up starts at its vertex (1,−8)(1,-8) and extends to infinity.
axis of symmetry:
(x = 1)
x intercept: (3,0) (-1,0)
y intercept: (0,-6)