Answer:
1. The ammount of tin needed
2. One of the bass is open radius 2.5 dm, height is 5 dm
3. y = 2.5 dm h = 5 dm
number = 25 { there are 25 milk tins }
4. s = ( π r² + 2× π r h) × 25 { one milk tin's area is πr²+2π rh}
5. (6.25π + 25π ) × 25
= 31.25π × 25
= 781. 25π {the answer is 781.25π }
Explanation:
I hope it helps you good luck!
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Answers & Comments
Answer:
1. The ammount of tin needed
2. One of the bass is open radius 2.5 dm, height is 5 dm
3. y = 2.5 dm h = 5 dm
number = 25 { there are 25 milk tins }
4. s = ( π r² + 2× π r h) × 25 { one milk tin's area is πr²+2π rh}
5. (6.25π + 25π ) × 25
= 31.25π × 25
= 781. 25π {the answer is 781.25π }
Explanation:
I hope it helps you good luck!