Answer:

C

2

​

H

6

​

​

+

7V

7O

2

​

​

⟶4

4V

CO

2

​

​

+6H

2

​

O

From the above reaction,

Amount of oxygen to react with 2V of ethane =7V

Given volume of ethane =600cc

∴ Amount of oxygen to react with 600cc of ethane =

2

7

​

×600=2100cc

Given voume of oxygen =2500cc

∴ Amount of oxygen left after reacting with 600cc of ethane =2500−2100=400cc

Now, again fromthe reaction,

Amount of CO

2

​

 formed in the combustion of  2V of ethane =4V

Given volume of ethane =600cc

∴ Amount of CO

2

​

 formed in the combustion of  600cc of ethane =

2

4

​

×600=1200cc

Hence the volume of unused oxygen is 400cc and the volume of carbon dioxide formed is 1200cc.

Explanation:

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Answer:

Given: 2C2H6+ 702 → 4CO2 + 6H2O 2000 cc of O2 was burnt with 400 cc of ethane. Calculate the volume of CO2 formed and unused O2.

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