Let's find out the mean of heights of the non-fertilizer plants from the given table.
[tex] \sf = \frac{24.1 + 25.9 +25.4 + 24.1 + 35.6 }{5} cm[/tex]
[tex] \sf \: = \frac{135.1}{5} cm[/tex]
[tex] \sf \: = 27.02 \: cm[/tex]
Therefore average height of non-fertilizer plants is 27.02cm or approximately 27.0 cm
[tex] \boxed{ \pmb{ \bf \: option \: d)} \sf \: 27.0 \: cm\: is \: the \: correct \: answer}[/tex]
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Answer:
Mean heights is the sum of terms by number of terms
Here we have to find the mean heights of the plants with no fertilizer.... ie ist one mean.
Mean = 24.1 + 25.9 + 25.4 + 24.1 + 35.6 / 5
= 135.1 / 5
= 27.0 cm
Therefore the correct answer will be options
Therefore the correct answer will be options D. 27.0 cm
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Solution:-
Let's find out the mean of heights of the non-fertilizer plants from the given table.
[tex] \sf = \frac{24.1 + 25.9 +25.4 + 24.1 + 35.6 }{5} cm[/tex]
[tex] \sf \: = \frac{135.1}{5} cm[/tex]
[tex] \sf \: = 27.02 \: cm[/tex]
Therefore average height of non-fertilizer plants is 27.02cm or approximately 27.0 cm
[tex] \boxed{ \pmb{ \bf \: option \: d)} \sf \: 27.0 \: cm\: is \: the \: correct \: answer}[/tex]
___________________________________
Answer:
Mean heights is the sum of terms by number of terms
Here we have to find the mean heights of the plants with no fertilizer.... ie ist one mean.
Mean = 24.1 + 25.9 + 25.4 + 24.1 + 35.6 / 5
= 135.1 / 5
= 27.0 cm
Therefore the correct answer will be options
Therefore the correct answer will be options D. 27.0 cm