I and m are two parallel lines intersected by another pair of parallel lines p and q (see Fig. 7.19). Show that triangle ABC congruent to triangle CDA.
THATS ACCOUNT WILL BE DELETED IF THEY GIVE WRONG ANSWER. INCLUDING USAINI, KESM, SUBHENDU, MATHS PROFESIC ARYAN, LOVING STARS, AND MORE.......
THATS ACCOUNT WILL BE DELETED IF THEY GIVE WRONG ANSWER. INCLUDING USAINI, KESM, SUBHENDU, MATHS PROFESIC ARYAN, LOVING STARS, AND MORE.......
Answers & Comments
It seems like you're describing a situation involving parallel lines and triangles. To help you, I would need more context or information about the figure you mentioned, such as the positions of points A, B, C, and D. Could you provide more details or clarify the relationships between these elements?
Verified answer
[tex]\huge{\underline{\underline{\pmb{\mathtt{\red{A}\pink{n}\green{s}\blue{w}\orange{e}\purple{R}}}}}}[/tex]
we can show it easily using ASA congruency rule
In △ABC and △CDA
AC=CA (Common)
∠BAC=∠DCA (Alternate interior angles, as p∥q)
∠BCA=∠DAC (Alternate interior angles, as l∥m)
∴△ABC≅△CDA (By ASA congruence rule)