PB parallel to CQ
so, 70 = 20 + y ( due to corresponding angles are equal)
y = 70 - 20
y = 50
BC = AC
So In triangle ABC,
A=B = 50
C= 180-(50+50)
= 80
At angle C
80 + x + 70 = 180
150 + x = 180
x = 180 - 150
x = 30
So, option C is correct
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Answers & Comments
PB parallel to CQ
so, 70 = 20 + y ( due to corresponding angles are equal)
y = 70 - 20
y = 50
BC = AC
So In triangle ABC,
A=B = 50
C= 180-(50+50)
= 80
At angle C
80 + x + 70 = 180
150 + x = 180
x = 180 - 150
x = 30
So, option C is correct
So 70=20+y( due to corresponding angles are equal
y=70-20
y=50
In triangle ABC
A=B=50
C=180-(50+50)
C=180-100
C=80
A+angle C
80+X+70=180
150+X=180
X=180-150
X=30
here is ur solution hope it will help you a lot