Plugging the values of x as 1 in h(x) and (-2) in 3x.
= h(1) - j(-2)
= 3(1) - 5 - {3(-2)}
= 3 - 5 - (-6)
= 3 - 5 + 6
= 3 + 6 - 5
= 4
~
#CarryOnLearning
Please use this hashtag to support our friends and heroes in the medical field. Every use of this hashtag in your answer is equivalent to a peso donation made by Brainly to our medical front liners. Stay home, stay safe, and study with Brainly
Answers & Comments
Here we have the polynomials:
We need to FinD:
Plugging the values of x as 1 in h(x) and (-2) in 3x.
= h(1) - j(-2)
= 3(1) - 5 - {3(-2)}
= 3 - 5 - (-6)
= 3 - 5 + 6
= 3 + 6 - 5
= 4
~![\large{ \blue{ \sf{MynnsanElla}}} \large{ \blue{ \sf{MynnsanElla}}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Cblue%7B%20%5Csf%7BMynnsanElla%7D%7D%7D)
#CarryOnLearning
Please use this hashtag to support our friends and heroes in the medical field. Every use of this hashtag in your answer is equivalent to a peso donation made by Brainly to our medical front liners. Stay home, stay safe, and study with Brainly