Given,
u=36km/hr
=36×5/18=10m/s
v=0m/s (since the car stopped after 5 sec)
t=5 second
To find, acceleration (a) and displacement (s)
We know, v=u+at
Therefore, 10=0+a×5
=10=5a
or a=10/5=2m/s^2
Also, s=ut+1/2at^2
Therefore, s=0×5+1/2×2×5^2
s=5×5=25m
Implies, Acceleration is 2m/s^2 and Distance is 25 m
Hope it helps u...!!!..
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Answers & Comments
Given,
u=36km/hr
=36×5/18=10m/s
v=0m/s (since the car stopped after 5 sec)
t=5 second
To find, acceleration (a) and displacement (s)
We know, v=u+at
Therefore, 10=0+a×5
=10=5a
or a=10/5=2m/s^2
Also, s=ut+1/2at^2
Therefore, s=0×5+1/2×2×5^2
s=5×5=25m
Implies, Acceleration is 2m/s^2 and Distance is 25 m
Hope it helps u...!!!..