given, 

speed of man, Vm = 3km/hr

speed of river, Vr = 2km/hr

angle which the man makes with the direction of motion of river = 120

The resultant velocity of man can be calculated by the parallelogram law of vectors as,

angle between Vr and VR

now time required to cross the river = OB/VR

in trianle ABO, angleAOB = 90o - 79o = 11o

so, OB = AO/cos11o =  0.5/0.981 = 0.509

so time required = 0.509/2.6 = 0.196hr = 0.196x60x60 = 705.6s

Now the point  where he will reach is B, and the distance of  B from A = AB = AOtan11 =  0.097km 

                                                                                                                                           = 0.097x1000= 97m

Answer:

Time=1/3 hr or 20 min

point on opp. bank/drift=1/6 km

Explanation:

Resolving his speed.

At x axis-: -1.5√3 kmph

at y axis: 1.5 kmph

Now,

Width of river=500 m=500/1000 km

speed in y axis=1.5

so, time=width /speed =1/3 hr

net speed in y axis=2-1.5√3=0.5 kmph (approx.)

so drift=net speed in x axis*time=0.5*1/3=1/6km(ans)

hope this helps