Question ⬇⬇
A ship is moving westwards with the speed of 10km/hr and a ship B 100km South of A, is moving Northwards with the speed of 10km/hr. The time after which the distance between them becomes shortest, is :- a) 5 hr b)5√2 hr c)10√2 hr d)0hr
A ship is moving westwards with the speed of 10km/hr and a ship B 100km South of A, is moving Northwards with the speed of 10km/hr. The time after which the distance between them becomes shortest, is :- a) 5 hr b)5√2 hr c)10√2 hr d)0hr
Answers & Comments
Explanation:
It is clear from the diagram that the shortest distance between the ship A and B is PQ.
Here, Sin450=OQPQ
⟹PQ=100×21=502m
Also,
VAB=VA2+VB2=102+102=102km/h
So, the time taken to reach shortest path is
t=VABPQ=102502=5h
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