A motorist moving with a speed of 36 km/hr sees a child standing in the middle of the road. He applies brakes and brings the motor to rest in 5 seconds, just in time to save the child. Calculate the average retarding force on the vehicle, if mass of vehicle and the driver is 500 kg.
Please explain in a proper way.
Answers & Comments
Answer:
1000 N
Explanation:
Let u be the initial speed of the vehicle just before the brakes were applied.
i.e.,
u=36 km/hr=[(36×1000)/(60×60)] m/s
=10 m/s
The final velocity when the vehicle stops is
v = 0 m/s.
We could calculate the average acceleration using the relation
v = u +a t
0=10+a(5)
or
a = -10/5=-2m/s^2
This is the deceleration of the vehicle (-sign).
So the average retarding force is
Force=mass× acceleration= 500kg×2m/s^2=1000kg m/s^2
=1000 N
note that here we are only giving the magnitude of the force. This force is against the motion of the vehicle.
Verified answer
To calculate the average retarding force on the vehicle, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.
In this case, the force is the retarding force, the mass is the total mass of the vehicle and driver, and the acceleration can be determined from the change in velocity and the time taken.
Given:
First, we need to convert the initial velocity and final velocity from km/hr to m/s.
We know that 1 km/hr = 1000/3600 m/s = 5/18 m/s.
So, the initial velocity in m/s is (36 × 5/18) m/s = 10 m/s, and the final velocity is 0 m/s.
The change in velocity Δv is the difference between the initial and final velocities, which is (0 - 10) m/s = -10 m/s (negative sign indicates deceleration).
Next, we can calculate the acceleration using the formula:
Substituting the values:
Now, we can determine the retarding force (F) using Newton's second law:
Substituting the values:
The negative sign indicates that the retarding force acts opposite to the motion of the vehicle. Therefore, the average retarding force on the vehicle is 1000 N.
~Hope It helps.. ✨