Answer:
50 km/hr²
Explanation:
We can use the formula for acceleration:
a = (v - u) / t
where:
a = acceleration
v = final velocity = 50 km/hr
u = initial velocity = 0 km/hr (since the train starts from a stationary position)
t = time taken to reach the final velocity = 60 minutes = 1 hour
Substituting the values in the formula, we get:
a = (50 - 0) / 1
a = 50 km/hr²
Initial speed, u = 0 m/S^2
Final velocity v = 50 km/hr => 50*5/18 => 13.8 m/s [ 1km/hr = 1 * 5/18 m/s]
Time t = 60 min => 3600 sec
Formula:-
v = u + at ( where 'a' is the acceleration )
13.8 = 0 + a(3600)
a= 13.8/3600
a= 3.83* 10^-3
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Verified answer
Answer:
50 km/hr²
Explanation:
We can use the formula for acceleration:
a = (v - u) / t
where:
a = acceleration
v = final velocity = 50 km/hr
u = initial velocity = 0 km/hr (since the train starts from a stationary position)
t = time taken to reach the final velocity = 60 minutes = 1 hour
Substituting the values in the formula, we get:
a = (50 - 0) / 1
a = 50 km/hr²
Therefore, the acceleration of the train is 50 km/hr².
Answer:
Explanation:
Initial speed, u = 0 m/S^2
Final velocity v = 50 km/hr => 50*5/18 => 13.8 m/s [ 1km/hr = 1 * 5/18 m/s]
Time t = 60 min => 3600 sec
Formula:-
v = u + at ( where 'a' is the acceleration )
13.8 = 0 + a(3600)
a= 13.8/3600
a= 3.83* 10^-3