two boats leave the same port at the same time, but at different directions. The first boat travels at the rate of 250 mi/hr and the second boat travels at the rate of 300 mi/hr. If after 3 hours the two boats are 1000miles apart, what is the angle between their paths? when they leave the port? can you answer this with how to illustrate and the workings of the answers THANKS
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Answer:
73.98°
Step-by-step explanation:
the paths of 2 boats and the distance between them forms a triangle.
let a be the distance covered by 1st boat.
let b be the distance covered by 2nd boat.
let c be the distance of 2 boats after 3 hrs.
what is asked is the angle between their paths
lets say that is C as shown in the fig.
Sol.
length a = 250 mi/hr x 3hr = 750 mi.
length b = 300 mi/hr x 3hr = 900 mi.
length c = 1000mi
Use formula to get the angle between their paths.
-372,500 = -1,350,000Cos(C)
C= Acos( -372,500/-1,350,000)
C = 73.98°