Answer:

Step-by-step explanation:

Let the speed of the slower plane be x km/hr. Then the speed of the faster plane is (x + 50) km/hr.

When two objects move away from each other, their distance can be added together to get the total distance between them. So, after 6 hours, the distance traveled by the slower plane is 6x km and the distance traveled by the faster plane is 6(x + 50) km. The total distance between them is 5100 km.

Therefore, we can write an equation:

6x + 6(x + 50) = 5100

Simplifying and solving for x, we get:

12x + 300 = 5100

12x = 4800

x = 400

So, the speed of the slower plane is 400 km/hr and the speed of the faster plane is 450 km/hr.

Therefore, their average speeds are:

(400 km/hr + 450 km/hr) / 2 = 425 km/hr

Verified answer

Answer:

Let the speed of one plane be xkmphr

Then the speed of other plane is x+40kmphr

Distance travelled by first plane in 5hrs=speed×time=x×5=5x

Distance travelled by second plane in 5hrs=(x+40)×5

Distance traveled by first plane+Distance traveled by other plane=3400km

⇒5x+5(x+40)=3400

⇒5x+5x+200=3400

⇒10x=3400−200=3200

⇒x=

10

3200

=320kmphr

Speed of first plane=xkmphr=320kmphr

Speed of second plane=x+40=320+40=360kmphr

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