two towns A and B are 400 km apart Prakash and Jagdish started their cars from towns A and B respectively at the same time towards each other . When they were 10kilometers apart,the speed of prakash car exceeded the the speed of Jagdish car by 10km/hr , find their respective speeds.
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Answer:
Let the speed of Jagdish car be x km/hour.
The speed of prakash car exceeded the the speed of Jagdish car by 10km/hr
Speed of Prakash car be (x + 10) km/hour.
In 5 hours Jagdish and Prakash traveled 5x km and 5(x + 10) km respectively.
Total distance travelled by them = (400 - 10) km = 390 km.
5x + 5(x + 10) = 3905x +5(x +10)=390
10x + 50 = 39010x +50=390
10x = 34010x =340
x = 34x =34
Speed of Jagdish car = 34 km/hour.
Speed of Prakash car = (34 + 10) km/hour = 44 km/hour.
Hence Speed of jagdish and Prakash car is 34 km/hr and 44 k /hr respectively
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Step-by-step explanation:
Let the speed of Jagdish car be x km/hour.
∴ Speed of Prakash car be (x + 10) km/hour.
In 5 hours Jagdish and Prakash travelled 5x km and 5(x + 10) km respectively. Total distance travelled by them = (400 - 10) km = 390 km.
∴ 5x + 5(x + 10) = 390
⇒ 10x + 50 = 390
⇒ 10x = 340
⇒ x = 34
Speed of Jagdish car = 34 km/hour.
Speed of Prakash car = (34 + 10) km/hour = 44 km/hour.
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