A bus is traveling at 72km/hr . Brakes are applied the bus comes to a stop after 10 m . Find the retardation of the brakes.
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Using equation: v^2-u^2=2as
v=0 (because the bus stops), u=72km/hr= 20m/s, s=10m. So by substituting, 0^2-20^2=20a, a=(-20m/s^2)
Answer:
we know that for converting km/hr into m/s we have to multipy by 5/18 therefore; 72km/hr= 20m/s
ATP,
v=u+at
0=20+a(10)
0-20=10a
a=-20/10
a= -2m/s²
Retardation = 2m/s²
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