Step-by-step explanation:

the fricition is

\frac{1}{200?}

200?

1

mass of truck - 5tan

speed = 36 km / HR = 10 m/s

using the coefficient fruition omg = ma

using formula of fraction

f/w = 4mg / mg

f/w = u

f/w = u

put value of equation of motion

f/w = V2 -42 /25

put the value of formula

f/w - 100/2*10*1000

f/w - 1/200

Verified answer

Calculate the amount of work required to stop a truck of mass 5 tones which is moving at 36 km/hr.