nitthesh7
Let x = √6+√6+√6.....∞ ...1 then x = √6+x from 1 squaring on both sides x²=(√6+x)² x²=6+x =x²-x-6 =x²-3x+2x-6 =x(x-3)+2(x-3) =(x+2)(x-3) then x=-2,3
:)hope this ans would help u..
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nitthesh7
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then x = √6+x from 1
squaring on both sides
x²=(√6+x)²
x²=6+x
=x²-x-6
=x²-3x+2x-6
=x(x-3)+2(x-3)
=(x+2)(x-3)
then x=-2,3
:)hope this ans would help u..