Answer:
Let the number be x.So it's reciprocal is (1/x)
x + (1/x)=2[x-(1/x)],or
x^2+1=2x^2-2 or
x^2=3,so the number is √3.
Check √3=1.732 so 1/√3=0.577
Now x+(1/x)=2[x-(1/x)],r
LHS=1.732+(1/1.732)=2.309
RHS=2[1.732-(1/1.732)]=2*1.154=2.309
So the number is √3.
Step-by-step explanation:
#BrainliestPls#
#carryingOnLearning#
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Answers & Comments
Answer:
Let the number be x.So it's reciprocal is (1/x)
x + (1/x)=2[x-(1/x)],or
x^2+1=2x^2-2 or
x^2=3,so the number is √3.
Check √3=1.732 so 1/√3=0.577
Now x+(1/x)=2[x-(1/x)],r
LHS=1.732+(1/1.732)=2.309
RHS=2[1.732-(1/1.732)]=2*1.154=2.309
So the number is √3.
Step-by-step explanation:
#BrainliestPls#
#carryingOnLearning#