[Assuming the resistance of the filament was performed when deenergised and at ambient temp]
Initially we coulld use ohms law and know what the current would be cold. This would be worst case and o ly for a moment until the filament heats up.
This can be calculated I=V/R which in your case is 220/90=2.44Amps.
But then the filament would get hot, the resistance would shoot up and the current would decrease so I'm afraid that's as far as I can answer without knowing:
-How long the lamp is on for
-what material it is made from.
-is the voltage constant or connected to a grid?
Science is all about how far you want to go…. There are always many answers……
I made this simple video version for my electrical apprentices…
Answers & Comments
Answer:
It would depend at which point in time.
[Assuming the resistance of the filament was performed when deenergised and at ambient temp]
Initially we coulld use ohms law and know what the current would be cold. This would be worst case and o ly for a moment until the filament heats up.
This can be calculated I=V/R which in your case is 220/90=2.44Amps.
But then the filament would get hot, the resistance would shoot up and the current would decrease so I'm afraid that's as far as I can answer without knowing:
-How long the lamp is on for
-what material it is made from.
-is the voltage constant or connected to a grid?
Science is all about how far you want to go…. There are always many answers……
I made this simple video version for my electrical apprentices…
Explanation:
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