Explanation:
To solve this problem, we can use the formula:
M1V1 = M2V2
Where:
M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume
Substituting the given values:
M1 = 9.0 M
V1 = 45 mL
M2 = 0.075 M1 = initial volume
We know that:
M1 = 9.0 M (because 45 ml of 9.0 M NaCl is the initial solution)
V1 = 45 ml
M2 = 0.075 M (because we want to make a 0.075 M NaCl solution)
V2 = ?
Now, we can solve for V2:
9.0 M x 45 ml = 0.075 M x V2
V2 = (9.0 M x 45 ml) / 0.075 M
V2 = 5400 ml or 5.4 L
Therefore, we can make 5.4 L of 0.075 M NaCl solution by diluting 45 ml of 9.0 M NaCl.
Answer:
V2 = ? Therefore, we can make 5.4 L of 0.075 M NaCl solution by diluting 45 ml of 9.0 M NaCl.
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Verified answer
Explanation:
To solve this problem, we can use the formula:
M1V1 = M2V2
Where:
M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume
Substituting the given values:
M1 = 9.0 M
V1 = 45 mL
M2 = 0.075 M1 = initial volume
M2 = final concentration
V2 = final volume
We know that:
M1 = 9.0 M (because 45 ml of 9.0 M NaCl is the initial solution)
V1 = 45 ml
M2 = 0.075 M (because we want to make a 0.075 M NaCl solution)
V2 = ?
Now, we can solve for V2:
M1V1 = M2V2
9.0 M x 45 ml = 0.075 M x V2
V2 = (9.0 M x 45 ml) / 0.075 M
V2 = 5400 ml or 5.4 L
Therefore, we can make 5.4 L of 0.075 M NaCl solution by diluting 45 ml of 9.0 M NaCl.
Answer:
V2 = ? Therefore, we can make 5.4 L of 0.075 M NaCl solution by diluting 45 ml of 9.0 M NaCl.