This can easily be proved by the congruence of alternate interior angles. From a given vertex of a polygon with n sides, (n-3) diagonals can be drawn. Every diagonal drawn from a single vertex of a polygon creates one triangle within the polygon, except for the last diagonal, which creates two
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Answer:
This can easily be proved by the congruence of alternate interior angles. From a given vertex of a polygon with n sides, (n-3) diagonals can be drawn. Every diagonal drawn from a single vertex of a polygon creates one triangle within the polygon, except for the last diagonal, which creates two
Step-by-step explanation:
so the answer is D.