Given,
Volume=55.5 l
At S.T.P
Pressure=1 atm
Temperature=298 K
R=0.083 l atm/K mol
We know,
PV=nRT
n=PV/RT
n=1×55.5/0.083×298
n=2.001 mol
Answer:
A: 22.4 L = 1mol
1mol
= 55.5 L x 22.4 L
= 2.48 mol of CO2.(Ans)
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Answers & Comments
Given,
Volume=55.5 l
At S.T.P
Pressure=1 atm
Temperature=298 K
R=0.083 l atm/K mol
We know,
PV=nRT
n=PV/RT
n=1×55.5/0.083×298
n=2.001 mol
Answer:
A: 22.4 L = 1mol
1mol
= 55.5 L x 22.4 L
= 2.48 mol of CO2.(Ans)