The molar mass of Fe is 55.845 grams (1 mole Fe = 55.845 grams Fe). The molar mass of O2 is 2 x 16.00 or 32.00 grams (1 mole O2 = 32.00 grams O2). The mass of a mole of Fe2O3 is (2 x Fe) + (3 x Oxygen) = (2 x 55.845) + (3 x 16.00) = 159.69 grams (1 mole of Fe2O3 = 159.69 grams Fe2O3)
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Answer:
The molar mass of Fe is 55.845 grams (1 mole Fe = 55.845 grams Fe). The molar mass of O2 is 2 x 16.00 or 32.00 grams (1 mole O2 = 32.00 grams O2). The mass of a mole of Fe2O3 is (2 x Fe) + (3 x Oxygen) = (2 x 55.845) + (3 x 16.00) = 159.69 grams (1 mole of Fe2O3 = 159.69 grams Fe2O3)
Explanation: