Answer:

20 is the answer if repetition is allowed but in your question it is stated that 'no repetition of digits".

The answer is 12 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7, and 9 which are divisible by 7 with no repetition of digits.

Step-by-step explanation:

For each of the two possible units digits (5 and 9), there are 3 choices for the hundreds digit (the units digit and the other two digits must be different), and 4 choices for the tens digit (the units digit and the hundreds digit must be different), making 3 * 4 = 12 different 3-digit numbers possible.

-> Pa award naman po ng BRAINLIEST, thank youuu <-