How many 2 digit numbers can be formed with the digits 3, 5, 6, 7, 8 if none of the digits is being repeated in any of the numbers so formed
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answer it and gets brainliest from me
plss answer it fast
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Answer:
Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.
The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.
The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.
∴ Required number of numbers = (1 x 5 x 4) = 20.