how long will a stone take to fall to the Ground from the top building 80 m high what is the velocity of the stone on reaching the ground
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Explanation:
Intial velocity(u) = 80 m
height (h) = 80m
acceleration due to gravity = 9.8 ms-2
According to the equations of motion,
h = ut+1/2gt^2
80 = 0×t+1/2×9.8×t^2
80 = 1/2×9.8t^2
80 = 4.9t^2
80/4.9 = t^2
800/49 = t^2
t^2 = 16.32
t = root of 16.32
t = 4.03 s
v is the final velocity
v = u+gt
v = 0+9.8×4.03
v = 9.8×4.03 = 39.494 = 39.5 m/s
Therefore time taken is 4.03s and the final velocity v acquired by the stone is 39.5m/s
Answer:
Explanation:
intial velocity(u) = 80 m
height (h) = 80m
acceleration due to gravity = 9.8 ms-2
According to the equations of motion,
h = ut+1/2gt^2
80 = 0×t+1/2×9.8×t^2
80 = 1/2×9.8t^2
80 = 4.9t^2
80/4.9 = t^2
800/49 = t^Intial velocity(u) = 80 m
height (h) = 80m
acceleration due to gravity = 9.8 ms-2
According to the equations of motion,
h = ut+1/2gt^2
80 = 0×t+1/2×9.8×t^2
80 = 1/2×9.8t^2
80 = 4.9t^2
80/4.9 = t^2
800/49 = t^2
t^2 = 16.32
t = root of 16.32
t = 4.03 s
v is the final velocity
v = u+gt
v = 0+9.8×4.03
v = 9.8×4.03 = 39.494 = 39.5 m/s
Therefore time taken is 4.03s and the final velocity v acquired by the stone is 39.5m/s
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Answer:
answer is 39.5 meter per second ..