According to Raoul's law, when a non-volatile solid is added to the solvent its vapour pressure decreases and now it would become equal to that of solid solvent at lower temperature. Thus, the freezing point of the solvent decreases.
Let T
f
o
be freezing point of pure solvent
T
be freezing point of solution
Then, increase in freezing point
ΔT
=T
−T
known as depression of freezing point.
By experiments we know
∝m where, m= molar conc. of solute in solution.
⇒ΔT
=K
m
where, K
= freezing point depression constant.
Hope it helps...
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Answers & Comments
According to Raoul's law, when a non-volatile solid is added to the solvent its vapour pressure decreases and now it would become equal to that of solid solvent at lower temperature. Thus, the freezing point of the solvent decreases.
Let T
f
o
be freezing point of pure solvent
T
f
be freezing point of solution
Then, increase in freezing point
ΔT
f
=T
f
−T
f
o
known as depression of freezing point.
By experiments we know
ΔT
f
∝m where, m= molar conc. of solute in solution.
⇒ΔT
f
=K
f
m
T
f
−T
f
o
=K
f
m
where, K
f
= freezing point depression constant.
Hope it helps...
Hola bud I just wanna talk with you pls Inbox me