Learn how to find the distancebetween two pointsby using distanceformula,which is an application of the Pythagoreantheorem.We can rewritethe Pythagorean theorem.
For example:d=√((×_2-×_1)²+(y_2-_1)²)find the distancebetweenany twopoints
To solveforthe distanceuse the formula for distanced =st or distanceequalsspeed times time.Rate and speed are similar since they both representsome distanceper unit time like miles per hour or kilometersper hour.If rate R is the same as speed s,r =s =d/t.
To solve for distance use the formula for distance d = st, or distance equals speed times time. Rate and speed are similar since they both represent some distance per unit time like miles per hour or kilometers per hour.
Distance formula: d = ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} d=(x2−x1)2+(y2−y1)2 - Linear Functions.
Answers & Comments
Answer:
Learn how to find the distance between two points by using distance formula, which is an application of the Pythagorean theorem. We can rewrite the Pythagorean theorem.
For example: d=√ ((×_2-×_1)² + (y_2-_1)² ) find the distance between any two points
To solve for the distance use the formula for distance d = st or distance equals speed times time. Rate and speed are similar since they both represent some distance per unit time like miles per hour or kilometers per hour. If rate R is the same as speed s,r = s = d/t.
Explanation:
Hope it helps
Pa brainliest
#CarryOnLearning
Answer:
To solve for distance use the formula for distance d = st, or distance equals speed times time. Rate and speed are similar since they both represent some distance per unit time like miles per hour or kilometers per hour.
Distance formula: d = ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} d=(x2−x1)2+(y2−y1)2 - Linear Functions.
Explanation: