By using logarithm table, I found log(36.12)=1.557
Now, just putting this :
loga=1.557−243loga=−22.4433
Now, taking antilog both sides, this becomes :
a=antilog(−7.481)
Now, by using anti-log table, I got this as
a=3.303×10−8
Now, as you all might have noticed that this is a lot longer method and this has larger probability of a student doing a mistake in the calculations etc.
Answers & Comments
Answer:
This is my answer...
Explanation:
While, I was solving a problem of Chemistry [Solid State] when I encountered an equation like :
a3=3.612×10−23
Where, a is just a quantity [Actually, it is the length of a cubic unit cell.]
I was required to find the cube-root of a3 as I had to use a to find another quantity which was actually my answer.
I know that the cube-root of a3 here can be found by using logarithm.
loga3=log(3.612×10−23)3loga=log(36.12×10−24)3loga=log(36.12)+log(10−24)3loga=log(36.12)−24loga=log(36.12)−243
By using logarithm table, I found log(36.12)=1.557
Now, just putting this :
loga=1.557−243loga=−22.4433
Now, taking antilog both sides, this becomes :
a=antilog(−7.481)
Now, by using anti-log table, I got this as
a=3.303×10−8
Now, as you all might have noticed that this is a lot longer method and this has larger probability of a student doing a mistake in the calculations etc.