Solve by Direct or Inverse method:
1. If the cost of 9kg of mangoes is ₹613.Find How many kg of mangoes may bought for ₹1140.
2. A distance of 1500km covered by a car in 25 hours. If speed of car is reduced to 50km/hour. Find the time taken.
1. If the cost of 9kg of mangoes is ₹613.Find How many kg of mangoes may bought for ₹1140.
2. A distance of 1500km covered by a car in 25 hours. If speed of car is reduced to 50km/hour. Find the time taken.
Answers & Comments
Answer:
1)16.73 kg mangoes may bought for $1140
2)sorry i can't solve the second question.
Verified answer
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1. Let's write it in ratio form; 9 : 613 :: x : 1140.
to write ratios you have to take the given of the thing that is described, in this question the price of 9kg mangoes is given. The amount as well as the price so we will write is as 9:613 . No units are used in ratio.
Now we will write the to find in ratio. We have to find the quantity of mangoes. Let's say it's x. So just like the first example, 9:613 , we will write this one with the quantity of mangoes first and then the price; x:1140.
So now we have 9:613::x:1140.
So the given is in this format A:B::C:D, The formula is AD= BC, So it will be 9×1140 = x × 613.
10,260 = 613×. × = 10260÷613 = 16.73 mangoes
2. speed= distance÷ time. 1500÷25 = 60.
1500- 50= 1450.
now we have to find time, time= distance× speed.
1450×60= 87hours.