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⭐Find the compond intrest on ₹12600 for 2 years at 10% per annum componded annually ⭐
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⭐Find the compond intrest on ₹12600 for 2 years at 10% per annum componded annually ⭐
❕NO GOOGLING ❕
⚡ QUALITY ANSWERS REQUIRED ⚡
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Find compound interest of rupees 12600 for 2 years at 10% per annum compounded annually
Answer
Given:-
P=₹12600
T=2
R=10%
Therefore A=?
A=P{1+R/100}^t
=12600{1+10/100}^2
=12600{100/100+10/100}^2
=12600{110/100}^2
=12600{11/10}{11/10}
=126×11×11
=₹15246
Therefore, Amount=₹15246
Therefore,C.I=Amount-Principle
=15246-12600
=₹2646
So,C.I=₹2646(Ans)
Hope this helps!!!
Given principal = 126000, Time n = 2 years, R = 10%.
We know that A = P(1 + r/100)^n
⇒ A = 12600(1 + 10/100)^2
= 12600(1 + 1/10)^2
= 12600(11/10)^2
= 12600(121/100)
= 126 * 121
= 15246.
We know that CI = A - P
⇒ 15246 - 12600
⇒ 2646.
Therefore, Compound interest = 2646.
Hope this helps!