3) ^7√a²+3 = ( a² + 3 ) ^1/7
4) √m+3 = ( m + 3 ) ^1/2
Explanation:
I_was_refered_^n √a² = a ^x/n
legit_po_yan!
\(^0^)/
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3) ^7√a²+3 = ( a² + 3 ) ^1/7
4) √m+3 = ( m + 3 ) ^1/2
Explanation:
I_was_refered_^n √a² = a ^x/n
legit_po_yan!
\(^0^)/